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1.1 ! root 1: /* ! 2: * Copyright (c) 1980 Regents of the University of California. ! 3: * All rights reserved. The Berkeley software License Agreement ! 4: * specifies the terms and conditions for redistribution. ! 5: */ ! 6: ! 7: #ifdef LIBC_SCCS ! 8: .asciz "@(#)atof.s 5.3 (Berkeley) 3/9/86" ! 9: #endif LIBC_SCCS ! 10: ! 11: #include "DEFS.h" ! 12: ! 13: /* ! 14: * atof: convert ascii to floating ! 15: * ! 16: * C usage: ! 17: * ! 18: * double atof (s) ! 19: * char *s; ! 20: * ! 21: * Register usage: ! 22: * ! 23: * r0-1: value being developed ! 24: * r2: first section: pointer to the next character ! 25: * second section: binary exponent ! 26: * r3: flags ! 27: * r4: first section: the current character ! 28: * second section: scratch ! 29: * r5: the decimal exponent ! 30: * r6-7: scratch ! 31: */ ! 32: .set msign,0 # mantissa has negative sign ! 33: .set esign,1 # exponent has negative sign ! 34: .set decpt,2 # decimal point encountered ! 35: ! 36: ENTRY(atof, R6|R7) ! 37: /* ! 38: * Initialization ! 39: */ ! 40: clrl r3 # All flags start out false ! 41: movl 4(ap),r2 # Address the first character ! 42: clrl r5 # Clear starting exponent ! 43: /* ! 44: * Skip leading white space ! 45: */ ! 46: sk0: movzbl (r2)+,r4 # Fetch the next (first) character ! 47: cmpb $' ,r4 # Is it blank? ! 48: jeql sk0 # ...yes ! 49: cmpb r4,$8 # 8 is lowest of white-space group ! 50: jlss sk1 # Jump if char too low to be white space ! 51: cmpb r4,$13 # 13 is highest of white-space group ! 52: jleq sk0 # Jump if character is white space ! 53: sk1: ! 54: /* ! 55: * Check for a sign ! 56: */ ! 57: cmpb $'+,r4 # Positive sign? ! 58: jeql cs1 # ... yes ! 59: cmpb $'-,r4 # Negative sign? ! 60: jneq cs2 # ... no ! 61: bisb2 $1<msign,r3 # Indicate a negative mantissa ! 62: cs1: movzbl (r2)+,r4 # Skip the character ! 63: cs2: ! 64: /* ! 65: * Accumulate digits, keeping track of the exponent ! 66: */ ! 67: clrq r0 # Clear the accumulator ! 68: ad0: cmpb r4,$'0 # Do we have a digit? ! 69: jlss ad4 # ... no, too small ! 70: cmpb r4,$'9 ! 71: jgtr ad4 # ... no, too large ! 72: /* ! 73: * We got a digit. Accumulate it ! 74: */ ! 75: cmpl r1,$214748364 # Would this digit cause overflow? ! 76: jgeq ad1 # ... yes ! 77: /* ! 78: * Multiply (r0,r1) by 10. This is done by developing ! 79: * (r0,r1)*2 in (r6,r7), shifting (r0,r1) left three bits, ! 80: * and adding the two quadwords. ! 81: */ ! 82: ashq $1,r0,r6 # (r6,r7)=(r0,r1)*2 ! 83: ashq $3,r0,r0 # (r0,r1)=(r0,r1)*8 ! 84: addl2 r6,r0 # Add low halves ! 85: adwc r7,r1 # Add high halves ! 86: /* ! 87: * Add in the digit ! 88: */ ! 89: subl2 $'0,r4 # Get the digit value ! 90: addl2 r4,r0 # Add it into the accumulator ! 91: adwc $0,r1 # Possible carry into high half ! 92: jbr ad2 # Join common code ! 93: /* ! 94: * Here when the digit won't fit in the accumulator ! 95: */ ! 96: ad1: incl r5 # Ignore the digit, bump exponent ! 97: /* ! 98: * If we have seen a decimal point, decrease the exponent by 1 ! 99: */ ! 100: ad2: jbc $decpt,r3,ad3 # Jump if decimal point not seen ! 101: decl r5 # Decrease exponent ! 102: ad3: ! 103: /* ! 104: * Fetch the next character, back for more ! 105: */ ! 106: movzbl (r2)+,r4 # Fetch ! 107: jbr ad0 # Try again ! 108: /* ! 109: * Not a digit. Could it be a decimal point? ! 110: */ ! 111: ad4: cmpb r4,$'. # If it's not a decimal point, either it's ! 112: jneq ad5 # the end of the number or the start of ! 113: # the exponent. ! 114: jbcs $decpt,r3,ad3 # If it IS a decimal point, we record that ! 115: # we've seen one, and keep collecting ! 116: # digits if it is the first one. ! 117: /* ! 118: * Check for an exponent ! 119: */ ! 120: ad5: clrl r6 # Initialize the exponent accumulator ! 121: ! 122: cmpb r4,$'e # We allow both lower case e ! 123: jeql ex1 # ... and ... ! 124: cmpb r4,$'E # upper-case E ! 125: jneq ex7 ! 126: /* ! 127: * Does the exponent have a sign? ! 128: */ ! 129: ex1: movzbl (r2)+,r4 # Get next character ! 130: cmpb r4,$'+ # Positive sign? ! 131: jeql ex2 # ... yes ... ! 132: cmpb r4,$'- # Negative sign? ! 133: jneq ex3 # ... no ... ! 134: bisb2 $1<esign,r3 # Indicate exponent is negative ! 135: ex2: movzbl (r2)+,r4 # Grab the next character ! 136: /* ! 137: * Accumulate exponent digits in r6 ! 138: */ ! 139: ex3: cmpb r4,$'0 # A digit is within the range ! 140: jlss ex4 # '0' through ! 141: cmpb r4,$'9 # '9', ! 142: jgtr ex4 # inclusive. ! 143: cmpl r6,$214748364 # Exponent outrageously large already? ! 144: jgeq ex2 # ... yes ! 145: moval (r6)[r6],r6 # r6 *= 5 ! 146: movaw -'0(r4)[r6],r6 # r6 = r6 * 2 + r4 - '0' ! 147: jbr ex2 # Go 'round again ! 148: ex4: ! 149: /* ! 150: * Now get the final exponent and force it within a reasonable ! 151: * range so our scaling loops don't take forever for values ! 152: * that will ultimately cause overflow or underflow anyway. ! 153: * A tight check on over/underflow will be done by ldexp. ! 154: */ ! 155: jbc $esign,r3,ex5 # Jump if exponent not negative ! 156: mnegl r6,r6 # If sign, negate exponent ! 157: ex5: addl2 r6,r5 # Add given exponent to calculated exponent ! 158: cmpl r5,$-100 # Absurdly small? ! 159: jgtr ex6 # ... no ! 160: movl $-100,r5 # ... yes, force within limit ! 161: ex6: cmpl r5,$100 # Absurdly large? ! 162: jlss ex7 # ... no ! 163: movl $100,r5 # ... yes, force within bounds ! 164: ex7: ! 165: /* ! 166: * Our number has now been reduced to a mantissa and an exponent. ! 167: * The mantissa is a 63-bit positive binary integer in r0,r1, ! 168: * and the exponent is a signed power of 10 in r5. The msign ! 169: * bit in r3 will be on if the mantissa should ultimately be ! 170: * considered negative. ! 171: * ! 172: * We now have to convert it to a standard format floating point ! 173: * number. This will be done by accumulating a binary exponent ! 174: * in r2, as we progressively get r5 closer to zero. ! 175: * ! 176: * Don't bother scaling if the mantissa is zero ! 177: */ ! 178: movq r0,r0 # Mantissa zero? ! 179: jeql exit # ... yes ! 180: ! 181: clrl r2 # Initialize binary exponent ! 182: tstl r5 # Which way to scale? ! 183: jleq sd0 # Scale down if decimal exponent <= 0 ! 184: /* ! 185: * Scale up by "multiplying" r0,r1 by 10 as many times as necessary, ! 186: * as follows: ! 187: * ! 188: * Step 1: Shift r0,r1 right as necessary to ensure that no ! 189: * overflow can occur when multiplying. ! 190: */ ! 191: su0: cmpl r1,$429496729 # Compare high word to (2**31)/5 ! 192: jlss su1 # Jump out if guaranteed safe ! 193: ashq $-1,r0,r0 # Else shift right one bit ! 194: incl r2 # bump exponent to compensate ! 195: jbr su0 # and go back to test again. ! 196: /* ! 197: * Step 2: Multiply r0,r1 by 5, by appropriate shifting and ! 198: * double-precision addition ! 199: */ ! 200: su1: ashq $2,r0,r6 # (r6,r7) := (r0,r1) * 4 ! 201: addl2 r6,r0 # Add low-order halves ! 202: adwc r7,r1 # and high-order halves ! 203: /* ! 204: * Step 3: Increment the binary exponent to take care of the final ! 205: * factor of 2, and go back if we still need to scale more. ! 206: */ ! 207: incl r2 # Increment the exponent ! 208: sobgtr r5,su0 # and back for more (maybe) ! 209: ! 210: jbr cm0 # Merge to build final value ! 211: ! 212: /* ! 213: * Scale down. We must "divide" r0,r1 by 10 as many times ! 214: * as needed, as follows: ! 215: * ! 216: * Step 0: Right now, the condition codes reflect the state ! 217: * of r5. If it's zero, we are done. ! 218: */ ! 219: sd0: jeql cm0 # If finished, build final number ! 220: /* ! 221: * Step 1: Shift r0,r1 left until the high-order bit (not counting ! 222: * the sign bit) is nonzero, so that the division will preserve ! 223: * as much precision as possible. ! 224: */ ! 225: tstl r1 # Is the entire high-order half zero? ! 226: jneq sd2 # ...no, go shift one bit at a time ! 227: ashq $30,r0,r0 # ...yes, shift left 30, ! 228: subl2 $30,r2 # decrement the exponent to compensate, ! 229: # and now it's known to be safe to shift ! 230: # at least once more. ! 231: sd1: ashq $1,r0,r0 # Shift (r0,r1) left one, and ! 232: decl r2 # decrement the exponent to compensate ! 233: sd2: jbc $30,r1,sd1 # If the high-order bit is off, go shift ! 234: /* ! 235: * Step 2: Divide the high-order part of (r0,r1) by 5, ! 236: * giving a quotient in r1 and a remainder in r7. ! 237: */ ! 238: sd3: movl r1,r6 # Copy the high-order part ! 239: clrl r7 # Zero-extend to 64 bits ! 240: ediv $5,r6,r1,r7 # Divide (cannot overflow) ! 241: /* ! 242: * Step 3: Divide the low-order part of (r0,r1) by 5, ! 243: * using the remainder from step 2 for rounding. ! 244: * Note that the result of this computation is unsigned, ! 245: * so we have to allow for the fact that an ordinary division ! 246: * by 5 could overflow. We make allowance by dividing by 10, ! 247: * multiplying the quotient by 2, and using the remainder ! 248: * to adjust the modified quotient. ! 249: */ ! 250: addl3 $2,r0,r6 # Dividend is low part of (r0,r1) plus ! 251: adwc $0,r7 # 2 for rounding plus ! 252: # (2**32) * previous remainder ! 253: ediv $10,r6,r0,r6 # r0 := quotient, r6 := remainder. ! 254: addl2 r0,r0 # Make r0 result of dividing by 5 ! 255: cmpl r6,$5 # If remainder is 5 or greater, ! 256: jlss sd4 # increment the adjustted quotient. ! 257: incl r0 ! 258: /* ! 259: * Step 4: Increment the decimal exponent, decrement the binary ! 260: * exponent (to make the division by 5 into a division by 10), ! 261: * and back for another iteration. ! 262: */ ! 263: sd4: decl r2 # Binary exponent ! 264: aoblss $0,r5,sd2 ! 265: /* ! 266: * We now have the following: ! 267: * ! 268: * r0: low-order half of a 64-bit integer ! 269: * r1: high-order half of the same 64-bit integer ! 270: * r2: a binary exponent ! 271: * ! 272: * Our final result is the integer represented by (r0,r1) ! 273: * multiplied by 2 to the power contained in r2. ! 274: * We will transform (r0,r1) into a floating-point value, ! 275: * set the sign appropriately, and let ldexp do the ! 276: * rest of the work. ! 277: * ! 278: * Step 1: if the high-order bit (excluding the sign) of ! 279: * the high-order half (r1) is 1, then we have 63 bits of ! 280: * fraction, too many to convert easily. However, we also ! 281: * know we won't need them all, so we will just throw the ! 282: * low-order bit away (and adjust the exponent appropriately). ! 283: */ ! 284: cm0: jbc $30,r1,cm1 # jump if no adjustment needed ! 285: ashq $-1,r0,r0 # lose the low-order bit ! 286: incl r2 # increase the exponent to compensate ! 287: /* ! 288: * Step 2: split the 62-bit number in (r0,r1) into two ! 289: * 31-bit positive quantities ! 290: */ ! 291: cm1: ashq $1,r0,r0 # put the high-order bits in r1 ! 292: # and a 0 in the bottom of r0 ! 293: rotl $-1,r0,r0 # right-justify the bits in r0 ! 294: # moving the 0 from the ashq ! 295: # into the sign bit. ! 296: /* ! 297: * Step 3: convert both halves to floating point ! 298: */ ! 299: cvtld r0,r6 # low-order part in r6-r7 ! 300: cvtld r1,r0 # high-order part in r0-r1 ! 301: /* ! 302: * Step 4: multiply the high order part by 2**31 and combine them ! 303: */ ! 304: muld2 two31,r0 # multiply ! 305: addd2 r6,r0 # combine ! 306: /* ! 307: * Step 5: if appropriate, negate the floating value ! 308: */ ! 309: jbc $msign,r3,cm2 # Jump if mantissa not signed ! 310: mnegd r0,r0 # If negative, make it so ! 311: /* ! 312: * Step 6: call ldexp to complete the job ! 313: */ ! 314: cm2: pushl r2 # Put exponent in parameter list ! 315: movd r0,-(sp) # and also mantissa ! 316: calls $3,_ldexp # go combine them ! 317: ! 318: exit: ! 319: ret ! 320: ! 321: .align 2 ! 322: two31: .word 0x5000 # 2 ** 31 ! 323: .word 0 # (=2147483648) ! 324: .word 0 # in floating-point ! 325: .word 0 # (so atof doesn't have to convert it)
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