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1.1 ! root 1: /* ! 2: * Copyright (c) 1988 Regents of the University of California. ! 3: * All rights reserved. The Berkeley software License Agreement ! 4: * specifies the terms and conditions for redistribution. ! 5: */ ! 6: ! 7: #if defined(LIBC_SCCS) && !defined(lint) ! 8: _sccsid:.asciz "@(#)atof.s 5.1 (Berkeley) 5/24/88" ! 9: #endif /* LIBC_SCCS and not lint */ ! 10: ! 11: #include "DEFS.h" ! 12: ! 13: /* ! 14: * atof: convert ascii to floating ! 15: * ! 16: * C usage: ! 17: * ! 18: * double atof (s) ! 19: * char *s; ! 20: * ! 21: * Register usage: ! 22: * ! 23: * r0-1: value being developed ! 24: * r2: first section: pointer to the next character ! 25: * second section: binary exponent ! 26: * r3: flags ! 27: * r4: first section: the current character ! 28: * second section: scratch ! 29: * r5: the decimal exponent ! 30: * r6-7: scratch ! 31: */ ! 32: .set msign,0 # mantissa has negative sign ! 33: .set esign,1 # exponent has negative sign ! 34: .set decpt,2 # decimal point encountered ! 35: ! 36: ENTRY(atof, R6|R7) ! 37: /* ! 38: * Initialization ! 39: */ ! 40: clrl r3 # All flags start out false ! 41: movl 4(fp),r2 # Address the first character ! 42: clrl r5 # Clear starting exponent ! 43: /* ! 44: * Skip leading white space ! 45: */ ! 46: sk0: movzbl (r2),r4 # Fetch the next (first) character ! 47: incl r2 ! 48: cmpb $' ,r4 # Is it blank? ! 49: beql sk0 # ...yes ! 50: cmpb r4,$8 # 8 is lowest of white-space group ! 51: blss sk1 # Jump if char too low to be white space ! 52: cmpb r4,$13 # 13 is highest of white-space group ! 53: bleq sk0 # Jump if character is white space ! 54: sk1: ! 55: /* ! 56: * Check for a sign ! 57: */ ! 58: cmpb $'+,r4 # Positive sign? ! 59: beql cs1 # ... yes ! 60: cmpb $'-,r4 # Negative sign? ! 61: bneq cs2 # ... no ! 62: orb2 $1<msign,r3 # Indicate a negative mantissa ! 63: cs1: movzbl (r2),r4 # Skip the character ! 64: incl r2 ! 65: cs2: ! 66: /* ! 67: * Accumulate digits, keeping track of the exponent ! 68: */ ! 69: clrl r1 ! 70: clrl r0 # Clear the accumulator ! 71: ad0: cmpb r4,$'0 # Do we have a digit? ! 72: blss ad4 # ... no, too small ! 73: cmpb r4,$'9 ! 74: bgtr ad4 # ... no, too large ! 75: /* ! 76: * We got a digit. Accumulate it ! 77: */ ! 78: cmpl r0,$214748364 # Would this digit cause overflow? ! 79: bgeq ad1 # ... yes ! 80: /* ! 81: * Multiply (r0,r1) by 10. This is done by developing ! 82: * (r0,r1)*2 in (r6,r7), shifting (r0,r1) left three bits, ! 83: * and adding the two quadwords. ! 84: */ ! 85: shlq $1,r0,r6 # (r6,r7)=(r0,r1)*2 ! 86: shlq $3,r0,r0 # (r0,r1)=(r0,r1)*8 ! 87: addl2 r7,r1 # Add low halves ! 88: adwc r6,r0 # Add high halves ! 89: /* ! 90: * Add in the digit ! 91: */ ! 92: subl2 $'0,r4 # Get the digit value ! 93: addl2 r4,r1 # Add it into the accumulator ! 94: adwc $0,r0 # Possible carry into high half ! 95: brb ad2 # Join common code ! 96: /* ! 97: * Here when the digit won't fit in the accumulator ! 98: */ ! 99: ad1: incl r5 # Ignore the digit, bump exponent ! 100: /* ! 101: * If we have seen a decimal point, decrease the exponent by 1 ! 102: */ ! 103: ad2: bbc $decpt,r3,ad3 # Jump if decimal point not seen ! 104: decl r5 # Decrease exponent ! 105: ad3: ! 106: /* ! 107: * Fetch the next character, back for more ! 108: */ ! 109: movzbl (r2),r4 # Fetch ! 110: incl r2 ! 111: brb ad0 # Try again ! 112: /* ! 113: * Not a digit. Could it be a decimal point? ! 114: */ ! 115: ad4: cmpb r4,$'. # If it's not a decimal point, either it's ! 116: bneq ad5 # the end of the number or the start of ! 117: # the exponent. ! 118: bbs $decpt,r3,ad5 ! 119: orb2 $1<decpt,r3 # If it IS a decimal point, we record that ! 120: brb ad3 # we've seen one, and keep collecting ! 121: # digits if it is the first one. ! 122: ! 123: /* ! 124: * Check for an exponent ! 125: */ ! 126: ad5: clrl r6 # Initialize the exponent accumulator ! 127: ! 128: cmpb r4,$'e # We allow both lower case e ! 129: beql ex1 # ... and ... ! 130: cmpb r4,$'E # upper-case E ! 131: bneq ex7 ! 132: /* ! 133: * Does the exponent have a sign? ! 134: */ ! 135: ex1: movzbl (r2),r4 # Get next character ! 136: incl r2 ! 137: cmpb r4,$'+ # Positive sign? ! 138: beql ex2 # ... yes ... ! 139: cmpb r4,$'- # Negative sign? ! 140: bneq ex3 # ... no ... ! 141: orb2 $1<esign,r3 # Indicate exponent is negative ! 142: ex2: movzbl (r2),r4 # Grab the next character ! 143: incl r2 ! 144: /* ! 145: * Accumulate exponent digits in r6 ! 146: */ ! 147: ex3: cmpb r4,$'0 # A digit is within the range ! 148: blss ex4 # '0' through ! 149: cmpb r4,$'9 # '9', ! 150: bgtr ex4 # inclusive. ! 151: cmpl r6,$214748364 # Exponent outrageously large already? ! 152: bgeq ex2 # ... yes ! 153: moval (r6)[r6],r6 # r6 *= 5 ! 154: movaw -'0(r4)[r6],r6 # r6 = r6 * 2 + r4 - '0' ! 155: brb ex2 # Go 'round again ! 156: ex4: ! 157: /* ! 158: * Now get the final exponent and force it within a reasonable ! 159: * range so our scaling loops don't take forever for values ! 160: * that will ultimately cause overflow or underflow anyway. ! 161: * A tight check on over/underflow will be done by ldexp. ! 162: */ ! 163: bbc $esign,r3,ex5 # Jump if exponent not negative ! 164: mnegl r6,r6 # If sign, negate exponent ! 165: ex5: addl2 r6,r5 # Add given exponent to calculated exponent ! 166: cmpl r5,$-100 # Absurdly small? ! 167: bgtr ex6 # ... no ! 168: movl $-100,r5 # ... yes, force within limit ! 169: ex6: cmpl r5,$100 # Absurdly large? ! 170: blss ex7 # ... no ! 171: movl $100,r5 # ... yes, force within bounds ! 172: ex7: ! 173: /* ! 174: * Our number has now been reduced to a mantissa and an exponent. ! 175: * The mantissa is a 63-bit positive binary integer in r0,r1, ! 176: * and the exponent is a signed power of 10 in r5. The msign ! 177: * bit in r3 will be on if the mantissa should ultimately be ! 178: * considered negative. ! 179: * ! 180: * We now have to convert it to a standard format floating point ! 181: * number. This will be done by accumulating a binary exponent ! 182: * in r2, as we progressively get r5 closer to zero. ! 183: * ! 184: * Don't bother scaling if the mantissa is zero ! 185: */ ! 186: tstl r1 ! 187: bneq 1f ! 188: tstl r0 # Mantissa zero? ! 189: jeql exit # ... yes ! 190: ! 191: 1: clrl r2 # Initialize binary exponent ! 192: tstl r5 # Which way to scale? ! 193: bleq sd0 # Scale down if decimal exponent <= 0 ! 194: /* ! 195: * Scale up by "multiplying" r0,r1 by 10 as many times as necessary, ! 196: * as follows: ! 197: * ! 198: * Step 1: Shift r0,r1 right as necessary to ensure that no ! 199: * overflow can occur when multiplying. ! 200: */ ! 201: su0: cmpl r0,$429496729 # Compare high word to (2**31)/5 ! 202: blss su1 # Jump out if guaranteed safe ! 203: shrq $1,r0,r0 # Else shift right one bit ! 204: incl r2 # bump exponent to compensate ! 205: brb su0 # and go back to test again. ! 206: /* ! 207: * Step 2: Multiply r0,r1 by 5, by appropriate shifting and ! 208: * double-precision addition ! 209: */ ! 210: su1: shlq $2,r0,r6 # (r6,r7) := (r0,r1) * 4 ! 211: addl2 r7,r1 # Add low-order halves ! 212: adwc r6,r0 # and high-order halves ! 213: /* ! 214: * Step 3: Increment the binary exponent to take care of the final ! 215: * factor of 2, and go back if we still need to scale more. ! 216: */ ! 217: incl r2 # Increment the exponent ! 218: decl r5 # ...sobgtr r5,su0 ! 219: bgtr su0 # and back for more (maybe) ! 220: ! 221: brb cm0 # Merge to build final value ! 222: ! 223: /* ! 224: * Scale down. We must "divide" r0,r1 by 10 as many times ! 225: * as needed, as follows: ! 226: * ! 227: * Step 0: Right now, the condition codes reflect the state ! 228: * of r5. If it's zero, we are done. ! 229: */ ! 230: sd0: beql cm0 # If finished, build final number ! 231: /* ! 232: * Step 1: Shift r0,r1 left until the high-order bit (not counting ! 233: * the sign bit) is nonzero, so that the division will preserve ! 234: * as much precision as possible. ! 235: */ ! 236: tstl r0 # Is the entire high-order half zero? ! 237: bneq sd2 # ...no, go shift one bit at a time ! 238: shlq $30,r0,r0 # ...yes, shift left 30, ! 239: subl2 $30,r2 # decrement the exponent to compensate, ! 240: # and now it's known to be safe to shift ! 241: # at least once more. ! 242: sd1: shlq $1,r0,r0 # Shift (r0,r1) left one, and ! 243: decl r2 # decrement the exponent to compensate ! 244: sd2: bbc $30,r0,sd1 # If the high-order bit is off, go shift ! 245: /* ! 246: * Step 2: Divide the high-order part of (r0,r1) by 5, ! 247: * giving a quotient in r1 and a remainder in r7. ! 248: */ ! 249: sd3: movl r0,r7 # Copy the high-order part ! 250: clrl r6 # Zero-extend to 64 bits ! 251: ediv $5,r6,r0,r6 # Divide (cannot overflow) ! 252: /* ! 253: * Step 3: Divide the low-order part of (r0,r1) by 5, ! 254: * using the remainder from step 2 for rounding. ! 255: * Note that the result of this computation is unsigned, ! 256: * so we have to allow for the fact that an ordinary division ! 257: * by 5 could overflow. We make allowance by dividing by 10, ! 258: * multiplying the quotient by 2, and using the remainder ! 259: * to adjust the modified quotient. ! 260: */ ! 261: addl3 $2,r1,r7 # Dividend is low part of (r0,r1) plus ! 262: adwc $0,r6 # 2 for rounding plus ! 263: # (2**32) * previous remainder ! 264: ediv $10,r6,r1,r7 # r1 := quotient, r7 := remainder. ! 265: addl2 r1,r1 # Make r1 result of dividing by 5 ! 266: cmpl r7,$5 # If remainder is 5 or greater, ! 267: blss sd4 # increment the adjustted quotient. ! 268: incl r1 ! 269: /* ! 270: * Step 4: Increment the decimal exponent, decrement the binary ! 271: * exponent (to make the division by 5 into a division by 10), ! 272: * and back for another iteration. ! 273: */ ! 274: sd4: decl r2 # Binary exponent ! 275: aoblss $0,r5,sd2 ! 276: /* ! 277: * We now have the following: ! 278: * ! 279: * r0: high-order half of a 64-bit integer ! 280: * r1: load-order half of the same 64-bit integer ! 281: * r2: a binary exponent ! 282: * ! 283: * Our final result is the integer represented by (r0,r1) ! 284: * multiplied by 2 to the power contained in r2. ! 285: * We will transform (r0,r1) into a floating-point value, ! 286: * set the sign appropriately, and let ldexp do the ! 287: * rest of the work. ! 288: * ! 289: * Step 1: if the high-order bit (excluding the sign) of ! 290: * the high-order half (r0) is 1, then we have 63 bits of ! 291: * fraction, too many to convert easily. However, we also ! 292: * know we won't need them all, so we will just throw the ! 293: * low-order bit away (and adjust the exponent appropriately). ! 294: */ ! 295: cm0: bbc $30,r0,cm1 # jump if no adjustment needed ! 296: shrq $1,r0,r0 # lose the low-order bit ! 297: incl r2 # increase the exponent to compensate ! 298: /* ! 299: * Step 2: split the 62-bit number in (r0,r1) into two ! 300: * 31-bit positive quantities ! 301: */ ! 302: cm1: shlq $1,r0,r0 # put the high-order bits in r0 ! 303: # and a 0 in the bottom of r1 ! 304: shrl $1,r1,r1 # right-justify the bits in r1 ! 305: # moving 0 into the sign bit. ! 306: /* ! 307: * Step 3: convert both halves to floating point ! 308: */ ! 309: cvld r1 ! 310: std r6 # low-order part in r6-r7 ! 311: cvld r0 ! 312: std r0 # high-order part in r0-r1 ! 313: /* ! 314: * Step 4: multiply the high order part by 2**31 and combine them ! 315: */ ! 316: ldd two31 ! 317: muld r0 # multiply ! 318: addd r6 # combine ! 319: /* ! 320: * Step 5: if appropriate, negate the floating value ! 321: */ ! 322: bbc $msign,r3,cm2 # Jump if mantissa not signed ! 323: negd # If negative, make it so ! 324: /* ! 325: * Step 6: call ldexp to complete the job ! 326: */ ! 327: cm2: pushl r2 # Put exponent in parameter list ! 328: pushd # and also mantissa ! 329: calls $3,_ldexp # go combine them ! 330: ! 331: exit: ! 332: ret ! 333: ! 334: .align 2 ! 335: two31: .long 0x50000000 # (=2147483648) 2 ** 31 in floating-point ! 336: .long 0 # so atof doesn't have to convert it
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