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1.1 root 1: .align 1
2: .globl _calqhat
3: _calqhat:
4: .word 0xffc
5: movl 4(fp),r11 # &u[j] into r11
6: movl 8(fp),r10 # &v[1] into r10
7: cmpl (r10),(r11) # v[1] == u[j] ??
8: beql L102
9: # calculate qhat and rhat simultaneously,
10: # qhat in r0
11: # rhat in r1
12: emul (r11),$0x40000000,4(r11),r4 # u[j]b+u[j+1] into r4,r5
13: ediv (r10),r4,r0,r1 # qhat = ((u[j]b+u[j+1])/v[1]) into r0
14: # (u[j]b+u[j+1] -qhat*v[1]) into r1
15: # called rhat
16: L101:
17: # check if v[2]*qhat > rhat*b+u[j+2]
18: emul r0,4(r10),$0,r2 # qhat*v[2] into r3,r2
19: emul r1,$0x40000000,8(r11),r8 #rhat*b + u[j+2] into r9,r8
20: # give up if r3,r2 <= r9,r8, otherwise iterate
21: addl2 $0,r2 # explicitly clear carry.
22: subl2 r8,r2 # perform r3,r2 - r9,r8
23: sbwc r9,r3
24: bleq L103 # give up if negative or equal
25: decl r0 # otherwise, qhat = qhat - 1
26: addl2 (r10),r1 # since dec'ed qhat, inc rhat by v[1]
27: jbr L101
28: L102:
29: # get here if v[1]==u[j]
30: # set qhat to b-1
31: # rhat is easily calculated since if we substitute b-1 for qhat in
32: # the formula, then it simplifies to (u[j+1] + v[1])
33: #
34: addl3 4(r11),(r10),r1 # rhat = u[j+1] + v[1]
35: movl $0x3fffffff,r0 # qhat = b-1
36: jbr L101
37:
38: L103:
39: ret
40:
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