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1.1 root 1: #include "e.h"
2: #include "y.tab.h"
3:
4: pile(oct)
5: int oct;
6: {
7: int i, nlist, nlist2, mid;
8: float bi, hi, h, b, gap, sb;
9: extern float Pilegap, Pilebase;
10: int type, p1, p2;
11:
12: yyval = salloc();
13: type = lp[oct];
14: p1 = oct + 3; /* first entry */
15: p2 = p1 + lp[oct+1]; /* 1 after last */
16: gap = lp[oct+2];
17: if (gap != DEFGAP)
18: gap = EM(gap/100.0, ps);
19: else if (type == COL)
20: gap = 0;
21: else
22: gap = EM(Pilegap, ps); /* 0.4 m between LCOL, etc. */
23: nlist = p2 - p1;
24: nlist2 = (nlist+1)/2;
25: mid = p1 + nlist2 - 1;
26: h = 0;
27: for (i = p1; i < p2; i++)
28: h += eht[lp[i]];
29: eht[yyval] = h + (nlist-1)*gap;
30: b = 0;
31: for (i = p2-1; i > mid; i--)
32: b += eht[lp[i]] + gap;
33: ebase[yyval] = (nlist%2) ? b + ebase[lp[mid]]
34: : b - EM(Pilebase, ps) - gap;
35: if (dbg) {
36: printf(".\tS%d <- %d pile of:", yyval, type);
37: for (i = p1; i < p2; i++)
38: printf(" S%d", lp[i]);
39: printf("; h=%g b=%g\n", eht[yyval], ebase[yyval]);
40: }
41: nrwid(lp[p1], ps, lp[p1]);
42: printf(".nr %d \\n(%d\n", yyval, lp[p1]);
43: for (i = p1+1; i < p2; i++) {
44: nrwid(lp[i], ps, lp[i]);
45: printf(".if \\n(%d>\\n(%d .nr %d \\n(%d\n",
46: lp[i], yyval, yyval, lp[i]);
47: }
48: printf(".ds %d \\v'%gm'\\h'%du*\\n(%du'\\\n", yyval, REL(ebase[yyval],ps),
49: type==RCOL ? 1 : 0, yyval);
50: sb = 0; /* sum of box hts */
51: for (i = p2-1; i >= p1; i--) {
52: bi = sb + ebase[lp[i]];
53: switch (type) {
54: case LCOL:
55: printf("\\v'%gm'\\*(%d\\h'-\\n(%du'\\v'%gm'\\\n",
56: REL(-bi,ps), lp[i], lp[i], REL(bi,ps));
57: break;
58: case RCOL:
59: printf("\\v'%gm'\\h'-\\n(%du'\\*(%d\\v'%gm'\\\n",
60: REL(-bi,ps), lp[i], lp[i], REL(bi,ps));
61: break;
62: case CCOL:
63: case COL:
64: printf("\\v'%gm'\\h'\\n(%du-\\n(%du/2u'\\*(%d",
65: REL(-bi,ps), yyval, lp[i], lp[i]);
66: printf("\\h'-\\n(%du-\\n(%du/2u'\\v'%gm'\\\n",
67: yyval, lp[i], REL(bi,ps));
68: break;
69: }
70: sb += eht[lp[i]] + gap;
71: }
72: printf("\\v'%gm'\\h'%du*\\n(%du'\n", REL(-ebase[yyval],ps),
73: type!=RCOL ? 1 : 0, yyval);
74: for (i = p1; i < p2; i++)
75: sfree(lp[i]);
76: lfont[yyval] = rfont[yyval] = 0;
77: }
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